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Card puzzles

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red+black

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For those that didn't see me post these on another forum, have a go at solving these. They're quite do-able, so no cheating (ie. google):

Logic Puzzle #1

A maths professor asks his two brightest students, Fred and Tom, to his office to solve a logic puzzle. He says that there are 16 cards in his drawer:

Clubs: K, Q, 6, 5, 4
Diamonds: A, 5
Hearts: A, Q, 4
Spades: J, 8, 7, 4, 3, 2

The professor picks one card at random and tells the rank only to Fred, and the suit only to Tom. The professor asks them if they can each logically work out which card he picked. The students think about it for a while:

Fred: I don't know what the card is.
Tom: I know you don't know what the card is.
Fred: Oh, I know what the card is now.
Tom: Oh, I also know what the card is now.

Which card did the professor pick from his drawer?

Logic Puzzle #2

Using a standard English deck of cards, arrange an Ace, King, Queen and Jack in a single row across, using just one card of each suit:

1. The Spade is not adjacent to the Diamond
2. The suits alternate in colour
3. No card is adjacent to its next in rank
4. The King and Queen are facing each other (not necessarily adjacent though)
5. Both the King and the Jack sport a moustache

In order from left to right, what are the four cards?
 

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Clubs: K, Q, 6, 5, 4
Diamonds: A, 5
Hearts: A, Q, 4
Spades: J, 8, 7, 4, 3, 2

The professor picks one card at random and tells the rank only to Fred, and the suit only to Tom.

Well if he tells the rank to Fred, and Fred still doesn't know, that narrows it down to either an A,Q,5,4 as there are more than 1 of those.

Thats all from me. :)
 
4 Spades???

I think that is the answer I just can't really think of how to word it without sounding foolish.
 
QueensofLeon said:
4 Spades???

I think that is the answer I just can't really think of how to word it without sounding foolish.
I'm looking for logical reasoning and the mathematical proof. The process is more important than the end result.
 
btw my answers above are whited out,

here is my "process", also whited out

Code:
[COLOR="White"]Clubs: K, Q, 6, 5, 4														
Diamonds: A, 5														
Hearts: A, Q, 4														
Spades: J, 8, 7, 4, 3, 2														


		a	k	q	j	10	9	8	7	6	5	4	3	2

Club			k	q						6	5	4		
D		a									5			
h		a		q								4		
s					j			8	7			4	3	2


		a	k	q	j	10	9	8	7	6	5	4	3	2

Club				q							5	4		
D		a									5			
h		a		q								4		
s												4		

Fred: I don't know what the card is.														
Tom: I know you don't know what the card is.														
Fred: Oh, I know what the card is now.														
Tom: Oh, I also know what the card is now.														

Which card did the professor pick from his drawer?[/COLOR]

odd one out gets the bikkies
 
Here's a tizzler for the poker board

Falchoon has 2 cars in his garage currently, (not counting the Mrs' go slow mobile).

One's an '86, one's an '05 both Aussie made. Name them ;)
 

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For everyone's information, I am yet to see a single correct answer for either of the two puzzles I posted.
 
red+black said:
So, no takers huh?

I'll have a go with the English deck over the weekend.




The answer to my question is ........ drumroll ........

1986 VL Commodore (the only car I've ever owned) & a
2005 VT Commodore
 

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Two more puzzles:

Take all the Aces, Kings, Queens and Jacks from a deck so that you have just these 16 cards. Arrange them into a 4 x 4 matrix such that each row, column, and major diagonal contains only one card of each rank and suit.

Shouldn't take more than 5 minutes. Note that the answer is not unique.

============================================================

Take the 5s, 6s and 7s of Spades, Hearts and Diamonds from a deck so that you have just these 9 cards, and arrange them as such:

5s 6s 7s
7h 5h 6h
6d 7d 5d


The objective is to move the cards around such that each and every row, column and diagonal of your final matrix equals 18. What is the least number of card moves required to achieve this? Note that swapping the positions of two cards counts as 2 card moves, not 1.
 
Borgsta said:
The 2nd one is impossible. 21 is 7,7,7 so unless you can remove cards it is impossible.
Ha Ha :D I made a mistake. It should have read 18 (not 21). I've edited the puzzle.
 
Its still impossible with 9 cards to make something diagonally equal the same. At the moment every row and column equals 18 and 1 diagonal does too.

However you cant change them to equal 18 every diagonal way. To do that you'd need to have 1 card on the same row. ie.

5 6 5
7 6 5
7 6 7

Both diagonals now are 18 but the rows and columns are screwed.
 
Your solution to puzzle #1 is incorrect:

"such that each row, column, and major diagonal contains only one card of each rank and suit.

Puzzle #2 can be solved and it's easier than you would think. You need to not only show the final matrix, but to indicate how many moves it took.
 

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