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Subnetting

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Cats2001!

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Can someone give me an example of how to work out a subnet? I'm totally confused - I dont even know where to begin!

I was given an address 192.168.10.0 and a mask of 255.255.255.240, and I was asked to get the 5th usable subnet.

Thats all the info I got. Where do I begin? Whats the 5th usable subnet? How would you work it out?
 
Originally posted by Cats2001!
Can someone give me an example of how to work out a subnet? I'm totally confused - I dont even know where to begin!

I was given an address 192.168.10.0 and a mask of 255.255.255.240, and I was asked to get the 5th usable subnet.

Thats all the info I got. Where do I begin? Whats the 5th usable subnet? How would you work it out?
Click to expand...

I am confused too lol...

Why were you told this .. and what for?
 
Re: Re: Subnetting

Originally posted by TheMase


I am confused too lol...

Why were you told this .. and what for?
Click to expand...

It is for a CISCO prac exam.

I have no idea about subnetting - thats the only thing that gets me. I can configure the router OK, but i cant get the bloody address to configure it with (subnet)!!!!!!!!!!!!
 
If you haven't done IP addressing before this will probably not make much sense but see how you go.

The address 192.168.10.0 is represented as
11000000.10101000.00001010.00000000 in binary.

You can work this out by typing each of the numbers 192,168,10,0 into a calculator and pressing the BIN button. The same can be done with the mask which is 11111111.11111111.11111111.11110000

The address is a CLASS C address (addresses in the range 192-223 (eg. 193.18.9.10) are Class C) This means that the first 3 octets (ie x.x.x.0) are used for the network number and the last octet is used for the hosts (individual computers,servers etc.) or the subnets. As the address is a CLASS C, when working out the subnets the first 3 octets can be ignored.
Looking at the mask, in the last octet the four ones indicate that there is 15 subnets (15 = 1111 in binary) and the four zeros indicate that there is 15 hosts on each subnet.
Subnet 1 would have the address
11111111.11111111.11111111.00010000
#2: 11111111.11111111.11111111.00100000
#3: 11111111.11111111.11111111.00110000

If you convert the underlined section of each subnet into binary you will have the number of each subnet i.e. 0010 = #2

If you are still stuck have a look at http://www.cisco.com/warp/public/701/3.html
 

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Originally posted by mustapha
If you haven't done IP addressing before this will probably not make much sense but see how you go.

The address 192.168.10.0 is represented as
11000000.10101000.00001010.00000000 in binary.

You can work this out by typing each of the numbers 192,168,10,0 into a calculator and pressing the BIN button. The same can be done with the mask which is 11111111.11111111.11111111.11110000

The address is a CLASS C address (addresses in the range 192-223 (eg. 193.18.9.10) are Class C) This means that the first 3 octets (ie x.x.x.0) are used for the network number and the last octet is used for the hosts (individual computers,servers etc.) or the subnets. As the address is a CLASS C, when working out the subnets the first 3 octets can be ignored.
Looking at the mask, in the last octet the four ones indicate that there is 15 subnets (15 = 1111 in binary) and the four zeros indicate that there is 15 hosts on each subnet.
Subnet 1 would have the address
11111111.11111111.11111111.00010000
#2: 11111111.11111111.11111111.00100000
#3: 11111111.11111111.11111111.00110000

If you convert the underlined section of each subnet into binary you will have the number of each subnet i.e. 0010 = #2

If you are still stuck have a look at http://www.cisco.com/warp/public/701/3.html
Click to expand...

Could you convert that to Chinese for me please?
 
#2: 11111111.11111111.11111111.00100000
#3: 11111111.11111111.11111111.00110000

and would the 4th one be .01110000, or isnt there a 4th one? (Still confused!!)
 
Originally posted by mustapha
If you haven't done IP addressing before this will probably not make much sense but see how you go.

The address 192.168.10.0 is represented as
11000000.10101000.00001010.00000000 in binary.

You can work this out by typing each of the numbers 192,168,10,0 into a calculator and pressing the BIN button. The same can be done with the mask which is 11111111.11111111.11111111.11110000

The address is a CLASS C address (addresses in the range 192-223 (eg. 193.18.9.10) are Class C) This means that the first 3 octets (ie x.x.x.0) are used for the network number and the last octet is used for the hosts (individual computers,servers etc.) or the subnets. As the address is a CLASS C, when working out the subnets the first 3 octets can be ignored.
Looking at the mask, in the last octet the four ones indicate that there is 15 subnets (15 = 1111 in binary) and the four zeros indicate that there is 15 hosts on each subnet.
Subnet 1 would have the address
11111111.11111111.11111111.00010000
#2: 11111111.11111111.11111111.00100000
#3: 11111111.11111111.11111111.00110000

If you convert the underlined section of each subnet into binary you will have the number of each subnet i.e. 0010 = #2

If you are still stuck have a look at http://www.cisco.com/warp/public/701/3.html
Click to expand...

Not too bad, i think i got most of it. Im serious too.
 
I actually didn't include something about the subnet. The first subnet would be

11000000.10101000.00001010.00010000
(192.168.10.16 in decimal notation)

because as it is a Class C the first three octets remain the same ie they make up the network part of the address and each subnet is on that network). The mask is just used to indicate which bits will be used for the subnet.

#2 11000000.10101000.00001010.00100000
(192.168.10.32 in decimal notation)

#3 11000000.10101000.00001010.00110000
(192.168.10.48) in decimal notation)

The fourth one would be

11000000.10101000.00001010.01000000
(192.168.10.64)
because 0100 is binary for 4.

Have a look at the IP addressing site as it explains it better with more examples.
 

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