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I came across this equation whilst reading a book. If 1 = 2, then 1 = any number...I am now afraid the world could explode because of this.
Anyway, all of the steps are perfectly legal except for one (good luck figuring out which one). You need to think back to high school algebra to follow this.
You may find the first step (a=b) the most confusing. But, this kind of thing is done all the time in Algebra. It's true for plenty of a's and b's. Assume that a is the number of ears on my head, and b is the number of ears on your head. In that case a=b.
a = b
multiply both sides by a
a^2 = a*b
subtract b^2 from both sides
a^2-b^2 = a*b-b^2
apply the distributive law to both sides
(a+b)(a-b) = b(a-b)
divide both sides by (a-b)
(a+b) = b
substitute all a's for b's (remember, if a = b you can do this)
a+a = a
regroup the two a's in the left side, and rename it 2a
2a = a
divide both sides by a
2 = 1
Anyway, all of the steps are perfectly legal except for one (good luck figuring out which one). You need to think back to high school algebra to follow this.
You may find the first step (a=b) the most confusing. But, this kind of thing is done all the time in Algebra. It's true for plenty of a's and b's. Assume that a is the number of ears on my head, and b is the number of ears on your head. In that case a=b.
a = b
multiply both sides by a
a^2 = a*b
subtract b^2 from both sides
a^2-b^2 = a*b-b^2
apply the distributive law to both sides
(a+b)(a-b) = b(a-b)
divide both sides by (a-b)
(a+b) = b
substitute all a's for b's (remember, if a = b you can do this)
a+a = a
regroup the two a's in the left side, and rename it 2a
2a = a
divide both sides by a
2 = 1










